9(a+1)=3[a-(2-a)]

Solution for 9(a+1)=3[a-(2-a)] equation:

Simplifying
9(a + 1) = 3[a + -1(2 + -1a)]

Reorder the terms:
9(1 + a) = 3[a + -1(2 + -1a)]
(1 * 9 + a * 9) = 3[a + -1(2 + -1a)]
(9 + 9a) = 3[a + -1(2 + -1a)]
9 + 9a = 3[a + (2 * -1 + -1a * -1)]
9 + 9a = 3[a + (-2 + 1a)]

Reorder the terms:
9 + 9a = 3[-2 + a + 1a]

Combine like terms: a + 1a = 2a
9 + 9a = 3[-2 + 2a]
9 + 9a = [-2 * 3 + 2a * 3]
9 + 9a = [-6 + 6a]

Solving
9 + 9a = -6 + 6a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-6a' to each side of the equation.
9 + 9a + -6a = -6 + 6a + -6a

Combine like terms: 9a + -6a = 3a
9 + 3a = -6 + 6a + -6a

Combine like terms: 6a + -6a = 0
9 + 3a = -6 + 0
9 + 3a = -6

Add '-9' to each side of the equation.
9 + -9 + 3a = -6 + -9

Combine like terms: 9 + -9 = 0
0 + 3a = -6 + -9
3a = -6 + -9

Combine like terms: -6 + -9 = -15
3a = -15

Divide each side by '3'.
a = -5

Simplifying
a = -5